Question
Use algebra tiles to find (6x2+10x+8)–(6x2+5x).
x2
x2
x2
x2
x2
x2
x
x
x
x
x
x
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x
1
1
1
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1
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1
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x2
x2
x2
x2
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x2
x
x
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x
Combine like terms. For example, write 3 instead of 1 + 1 + 1.
x2
x2
x2
x2
x2
x2
x
x
x
x
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1
1
1
1
1
1
1
1
–
x2
x2
x2
x2
x2
x2
x
x
x
x
x
Combine like terms. For example, write 3 instead of 1 + 1 + 1.
Answers
GPT-4o mini
To solve the expression \((6x^2 + 10x + 8) - (6x^2 + 5x)\) using algebra tiles, let's break it down step by step.
1. **Represent the first polynomial \(6x^2 + 10x + 8\)**:
- We have 6 tiles representing \(x^2\).
- We have 10 tiles representing \(x\).
- We have 8 unit tiles (1s).
2. **Represent the second polynomial \(6x^2 + 5x\)**:
- Again, we have 6 tiles representing \(x^2\).
- We have 5 tiles representing \(x\).
- There are no unit tiles (0).
3. **Now, subtract \( (6x^2 + 5x) \) from \( (6x^2 + 10x + 8) \)**:
- Subtract the \(x^2\) tiles:
- \(6x^2 - 6x^2 = 0x^2\)
- Subtract the \(x\) tiles:
- \(10x - 5x = 5x\)
- Subtract the constant tiles:
- \(8 - 0 = 8\)
So, combining these terms gives us:
\[
0x^2 + 5x + 8
\]
Since \(0x^2\) is not necessary to show, we simplify this to:
\[
5x + 8
\]
### Final Answer:
The result of the expression \((6x^2 + 10x + 8) - (6x^2 + 5x)\) is:
\[
5x + 8
\]
1. **Represent the first polynomial \(6x^2 + 10x + 8\)**:
- We have 6 tiles representing \(x^2\).
- We have 10 tiles representing \(x\).
- We have 8 unit tiles (1s).
2. **Represent the second polynomial \(6x^2 + 5x\)**:
- Again, we have 6 tiles representing \(x^2\).
- We have 5 tiles representing \(x\).
- There are no unit tiles (0).
3. **Now, subtract \( (6x^2 + 5x) \) from \( (6x^2 + 10x + 8) \)**:
- Subtract the \(x^2\) tiles:
- \(6x^2 - 6x^2 = 0x^2\)
- Subtract the \(x\) tiles:
- \(10x - 5x = 5x\)
- Subtract the constant tiles:
- \(8 - 0 = 8\)
So, combining these terms gives us:
\[
0x^2 + 5x + 8
\]
Since \(0x^2\) is not necessary to show, we simplify this to:
\[
5x + 8
\]
### Final Answer:
The result of the expression \((6x^2 + 10x + 8) - (6x^2 + 5x)\) is:
\[
5x + 8
\]