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Question

A circular dial is divided into 10 equal parts from the origin toward the circumference. The parts are labeled clockwise from 1 to 28 in increments of 3. Beginning directly to the right, they are marked as 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28. A needle is fixed vertically at the center, with the arrow pointing directly upward to the line between 22 and 25 at the top center of the dial.

If this spinner is to be spun once, how likely will it stop on a multiple of 9?

(1 point)
Responses

impossible
impossible

certain
certain

likely
likely

unlikely
unlikely
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Answer 1

To determine the likelihood of the spinner stopping on a multiple of 9, we first need to identify the multiples of 9 within the range of numbers present on the dial.

The values on the dial are: 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28.

Now, we will check for multiples of 9 among those numbers:

• 9 is not on the dial.
• 18 is not on the dial.
• 27 is not on the dial.

Since there are no multiples of 9 among the numbers labeled on the dial, the probability of the spinner stopping on a multiple of 9 is impossible.

Therefore, the correct response is: impossible.