Which of these lists correctly orders the binary numbers from smallest to largest?

Question

Choose 1 answer:
Choose 1 answer:
(Choice A) \[1010\], \[0101\], \[0110\], \[0011\]
A
\[1010\], \[0101\], \[0110\], \[0011\]
(Choice B) \[0011\], \[0101\], \[0110\], \[1010\]
B
\[0011\], \[0101\], \[0110\], \[1010\]
(Choice C) \[0011\], \[0110\], \[0101\], \[1010\]
C
\[0011\], \[0110\], \[0101\], \[1010\]
(Choice D) \[1010\], \[0110\], \[0101\], \[0011\]
D
\[1010\], \[0110\], \[0101\], \[0011\]

Answer 1

To determine which list correctly orders the binary numbers from smallest to largest, we first need to convert each binary number to its decimal equivalent.

1. \[0011\] in binary is \(3\) in decimal.
2. \[0101\] in binary is \(5\) in decimal.
3. \[0110\] in binary is \(6\) in decimal.
4. \[1010\] in binary is \(10\) in decimal.

Now let's list these conversions:

• \[0011\] → \(3\)
• \[0101\] → \(5\)
• \[0110\] → \(6\)
• \[1010\] → \(10\)

Now we can order them from smallest to largest based on their decimal values:

1. \[0011\] (3)
2. \[0101\] (5)
3. \[0110\] (6)
4. \[1010\] (10)

So the correct ordering from smallest to largest is: \[0011\], \[0101\], \[0110\], \[1010\].

Thus, the correct choice is: (Choice B) \[0011\], \[0101\], \[0110\], \[1010\].