Part E. The area of the figure below is _______ square units. (Type the answer in the blank beside the figure). You can decompose the figure or use the formula below.

Question

Area of trapezoid= b^1 + b^2/2 ×h
there is a pair of parallel sides in the shape
5 6 7

Answer 1

To find the area of a trapezoid, we can use the formula:

\[ \text{Area} = \frac{(b_1 + b_2)}{2} \times h \]

Where \( b_1 \) and \( b_2 \) are the lengths of the two parallel sides (bases), and \( h \) is the height.

In the figure you provided, we have the following dimensions for the parallel sides:

• \( b_1 = 5 \) units
• \( b_2 = 6 \) units

However, you mentioned "7" without specifying what it represents. If we consider it as the height \( h \), we can plug in the values into the formula:

\[ \text{Area} = \frac{(5 + 6)}{2} \times 7 \]

Calculating the area step-by-step:

1. Add the bases: \[ 5 + 6 = 11 \]

2. Divide by 2: \[ \frac{11}{2} = 5.5 \]

3. Multiply by the height: \[ 5.5 \times 7 = 38.5 \]

So the area of the trapezoid is \( 38.5 \) square units. Therefore, you can fill in the blank:

The area of the figure below is 38.5 square units.