To solve the system of equations:
- \( 6x + 2y = 8 \)
- \( x + 3y = -12 \)
Let's solve the second equation for \( x \):
\[ x = -12 - 3y \]
Now we'll substitute this expression for \( x \) into the first equation:
\[ 6(-12 - 3y) + 2y = 8 \]
Distributing \( 6 \):
\[ -72 - 18y + 2y = 8 \]
Combining like terms:
\[ -72 - 16y = 8 \]
Now, isolate \( -16y \):
\[ -16y = 8 + 72 \] \[ -16y = 80 \]
Now divide by -16:
\[ y = \frac{80}{-16} = -5 \]
Now substitute \( y = -5 \) back into the expression for \( x \):
\[ x = -12 - 3(-5) \] \[ x = -12 + 15 \] \[ x = 3 \]
So, the solution to the system is:
\[ x = 3, y = -5 \]
Thus, the correct answer is:
x = 3, y = -5.