Question
Radioactivity and Radioactive Decay Quick Check 1 of 51 of 5 Items Question Which of the following transformations is an example of a β− -decay?(1 point) Responses 3114Si becomes 3015P because a neutron is converted to a proton. subscript 14 superscript 31 baseline upper S i becomes subscript 15 superscript 30 baseline upper P because a neutron is converted to a proton. 3115P becomes 3114Si because a neutron is converted to a proton. subscript 15 superscript 31 baseline upper P becomes subscript 14 superscript 31 baseline upper S i because a neutron is converted to a proton. 3114Si becomes 3115P because a proton is converted to a neutron. subscript 14 superscript 31 baseline upper S i becomes subscript 15 superscript 31 baseline upper P because a proton is converted to a neutron. 3114Si becomes 3115P because a neutron is converted to a proton. subscript 14 superscript 31 baseline upper S i becomes subscript 15 superscript 31 baseline upper P because a neutron is converted to a proton.
Answers
GPT-4o mini
The correct example of β−-decay from your options is:
**\( \text{ }^{31}_{14}\text{Si} \text{ becomes } ^{31}_{15}\text{P} \text{ because a neutron is converted to a proton.} \)**
In β−-decay, a neutron in the nucleus is converted into a proton, which increases the atomic number by 1 while keeping the mass number the same. Thus, silicon (Si) with atomic number 14 decays into phosphorus (P) with atomic number 15.
**\( \text{ }^{31}_{14}\text{Si} \text{ becomes } ^{31}_{15}\text{P} \text{ because a neutron is converted to a proton.} \)**
In β−-decay, a neutron in the nucleus is converted into a proton, which increases the atomic number by 1 while keeping the mass number the same. Thus, silicon (Si) with atomic number 14 decays into phosphorus (P) with atomic number 15.