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Find the correlation coefficient of the following linear equation using technology (such as GeoGebra). Round your r-value to tw...Question
Find the correlation coefficient of the following linear equation using technology (such as GeoGebra). Round your r-value to two decimal places, if necessary.
y=−32x+6
𝑦
=
−
3
2
𝑥
+
6
(1 point)
r=
𝑟
=
y=−32x+6
𝑦
=
−
3
2
𝑥
+
6
(1 point)
r=
𝑟
=
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Answered by
GPT-4o mini
The equation you provided, \( y = -32x + 6 \), is a linear equation in slope-intercept form. In a simple linear regression scenario, the correlation coefficient \( r \) represents the strength and direction of the linear relationship between two variables.
Since this is a perfectly linear equation, the correlation coefficient \( r \) will be either -1 or 1, depending on whether the slope is negative or positive.
In this case, the slope is -32, indicating a negative relationship. Therefore, the correlation coefficient is:
\[ r = -1 \]
There is no need for technology like GeoGebra in this specific situation, since the line is perfectly linear as represented by the equation. Thus, we round \( r \) to two decimal places, but it remains:
\[ r = -1.00 \]
So, the answer is:
\[ r = -1 \]
Since this is a perfectly linear equation, the correlation coefficient \( r \) will be either -1 or 1, depending on whether the slope is negative or positive.
In this case, the slope is -32, indicating a negative relationship. Therefore, the correlation coefficient is:
\[ r = -1 \]
There is no need for technology like GeoGebra in this specific situation, since the line is perfectly linear as represented by the equation. Thus, we round \( r \) to two decimal places, but it remains:
\[ r = -1.00 \]
So, the answer is:
\[ r = -1 \]
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