Use the image to answer the question.

Question

A circular dial is divided into 10 equal parts from the origin toward the circumference. The parts are labeled clockwise from 1 to 28 in increments of 3. Beginning directly to the right, they are marked as 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28. A needle is fixed vertically at the center, with the arrow pointing directly upward to the line between 22 and 25 at the top center of the dial.

If this spinner is to be spun once, how likely will it stop on a multiple of 9?

(1 point)
Responses

impossible
impossible

unlikely
unlikely

certain
certain

likely

Answer 1

To determine the likelihood of the spinner stopping on a multiple of 9, we first identify the numbers marked on the dial: 1, 4, 7, 10, 13, 16, 19, 22, 25, and 28.

Next, we check which of these numbers are multiples of 9:

• The multiples of 9 that are less than or equal to 28 are 0, 9, 18, and 27.
• From our list of numbers, there are no multiples of 9 present.

Since there are no multiples of 9 on the dial, the probability of stopping on a multiple of 9 is zero.

Thus, the response is:

impossible