Question 1: Probability Calculation
For part 1, let's calculate the probability of a client choosing model B with a garage.
- There are 6 house models to choose from (A, B, C, D, E, F).
- For each model, there are 2 choices (garage or carport).
- Therefore, the total number of different combinations is \(6 \text{ models} \times 2 \text{ options} = 12\) possible choices.
Now, we’re interested in just one specific outcome: choosing model B with a garage. There is only 1 favorable outcome for this choice.
Thus, the probability of choosing model B with a garage is: \[ P(\text{Model B with Garage}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{1}{12} \]
So, the answer is: 112 (1 over 12)
Question 2: Displaying All Possible Choices
For part 2, we need to identify which chart correctly displays all possible choices a client has when selecting a new home from this builder.
Given that there are 6 models and each can have either a garage or a carport, the correct display needs to list every combination of model and type of parking (garage or carport).
The complete list of possible combinations is:
- Model A + garage
- Model A + carport
- Model B + garage
- Model B + carport
- Model C + garage
- Model C + carport
- Model D + garage
- Model D + carport
- Model E + garage
- Model E + carport
- Model F + garage
- Model F + carport
From the options provided, the correct chart that includes all combinations correctly is: Possible Choices Model A + garage Model A + carport Model B + garage Model B + carport Model C + garage Model C + carport Model D + garage Model D + carport Model E + garage Model E + carport Model F + garage Model F + carport
This includes every model with both a garage and a carport for each, fulfilling the requirement of all possible choices.