Question

Question 1
A large company plans to develop a private subdivision. There are 6 house models to choose from (models A, B, C, D, E, and F) and for each model, a client may opt to have a garage or a carport.

Part 1: What is the probability of a client who will choose model B with a garage?

(2 points)
Responses

36
3 sixths

26
2 sixths

212
2 over 12

112
1 over 12
Question 2
Part 2: Which chart correctly displays all the possible choices a client has when selecting a new home from this builder?(2 points)
Responses

Possible Choices
Model A + garage

Model B + garage

Model C + garage

Model D + garage

Model E + garage

Model F + garage



Possible Choices Model A + garage Model B + garage Model C + garage Model D + garage Model E + garage Model F + garage

Possible Choices
Model A + carport

Model B + carport

Model C + carport

Model D + garage

Model E + garage

Model F + garage

Possible Choices Model A + carport Model B + carport Model C + carport Model D + garage Model E + garage Model F + garage

Possible Choices
Model A + garage Model A + carport

Model B + garage Model B + carport

Model C + garage Model C + carport

Model D + garage Model D + carport

Model E + garage Model E + carport

Model F + garage Model F + carport

Possible Choices Model A + garage Model A + carport Model B + garage Model B + carport Model C + garage Model C + carport Model D + garage Model D + carport Model E + garage Model E + carport Model F + garage Model F + carport

Possible Choices
Model A + garage Model A + carport

Model B + garage Model B + carport

Model C + garage Model C + carport

Model D + garage

Model E + garage

Model F + garage

Possible Choices Model A + garage Model A + carport Model B + garage Model B + carport Model C + garage Model C + carport Model D + garage Model E + garage Model F + garage
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Answer 1

### Question 1: Probability Calculation

For part 1, let's calculate the probability of a client choosing model B with a garage.

1. There are 6 house models to choose from (A, B, C, D, E, F).
2. For each model, there are 2 choices (garage or carport).
3. Therefore, the total number of different combinations is \(6 \text{ models} \times 2 \text{ options} = 12\) possible choices.

Now, we’re interested in just one specific outcome: choosing model B with a garage. There is only 1 favorable outcome for this choice.

Thus, the probability of choosing model B with a garage is:
\[
P(\text{Model B with Garage}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} = \frac{1}{12}
\]

So, the answer is:
**112 (1 over 12)**

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### Question 2: Displaying All Possible Choices

For part 2, we need to identify which chart correctly displays all possible choices a client has when selecting a new home from this builder.

Given that there are 6 models and each can have either a garage or a carport, the correct display needs to list every combination of model and type of parking (garage or carport).

The complete list of possible combinations is:
- Model A + garage
- Model A + carport
- Model B + garage
- Model B + carport
- Model C + garage
- Model C + carport
- Model D + garage
- Model D + carport
- Model E + garage
- Model E + carport
- Model F + garage
- Model F + carport

From the options provided, the correct chart that includes all combinations correctly is:
**Possible Choices Model A + garage Model A + carport Model B + garage Model B + carport Model C + garage Model C + carport Model D + garage Model D + carport Model E + garage Model E + carport Model F + garage Model F + carport**

This includes every model with both a garage and a carport for each, fulfilling the requirement of all possible choices.