a wooden block of mass 2kg is placed on a horizontal surface.a horizontal force of 12N is exerted on it makes it to accelerate at 5m/s^-2 .find the frictional force acting between the surface

Answer 1

To find the frictional force acting between the surface and the wooden block, we can use Newton's second law of motion:

$$F_{net}=m\cdot a$$

where:

• $F_{net}$ is the net force acting on the block,
• $m$ is the mass of the block,
• $a$ is the acceleration of the block.

Given:

• Mass ($m$) = 2 kg
• Acceleration ($a$) = 5 m/s²
• Applied force ($F_{applied}$) = 12 N

1. Calculate the net force ($F_{net}$):

$$F_{net}=m\cdot a=2,\text{kg}\cdot 5,{\text{m/s}}^2=10,\text{N}$$

2. Determine the frictional force ($f$):

The net force is the difference between the applied force and the frictional force:

$$F_{net}=F_{applied}-f$$

Rearranging this gives:

$$f=F_{applied}-F_{net}$$

Substituting in the values we have:

$$f=12,\text{N}-10,\text{N}=2,\text{N}$$

Thus, the frictional force acting between the surface and the block is 2 N.