Question
Heavy Snowfall (H) 0.95 (Lines going to both Closed and Open). Light snowfall (L) 0.90 (Lines going both to Closed and Open). H (Heavy snowfall). L (Light snowfall). C (Closed). O (Open). The tree diagram relates the weather forecast and school closings. Find the probability (as a percent) that the school is closed tomorrow if there is a 65% chance for heavy snow.
0.90 (Light snow and Open)
0.95 (Heavy snow and Closed)
0.90 (Light snow and Open)
0.95 (Heavy snow and Closed)
Answers
GPT-4o mini
To find the probability that the school is closed tomorrow given that there is a 65% chance for heavy snow, we can use the law of total probability.
We have the following probabilities based on the weather conditions:
- Probability of heavy snow (H) = 0.65
- Probability of light snow (L) = 1 - 0.65 = 0.35
From the problem, we know:
- Probability of school being closed given heavy snow (C|H) = 0.95
- Probability of school being closed given light snow (C|L) = 1 - 0.90 = 0.10 (since the probability of being open is 0.90)
Now we can calculate the total probability of the school being closed (C):
\[
P(C) = P(C|H) \cdot P(H) + P(C|L) \cdot P(L)
\]
Substituting the values we have:
\[
P(C) = (0.95 \cdot 0.65) + (0.10 \cdot 0.35)
\]
Calculating each term:
1. \( 0.95 \cdot 0.65 = 0.6175 \)
2. \( 0.10 \cdot 0.35 = 0.035 \)
Now sum these results:
\[
P(C) = 0.6175 + 0.035 = 0.6525
\]
To express this probability as a percent, we multiply by 100:
\[
P(C) = 0.6525 \times 100 = 65.25\%
\]
Thus, the probability that the school is closed tomorrow is **65.25%**.
We have the following probabilities based on the weather conditions:
- Probability of heavy snow (H) = 0.65
- Probability of light snow (L) = 1 - 0.65 = 0.35
From the problem, we know:
- Probability of school being closed given heavy snow (C|H) = 0.95
- Probability of school being closed given light snow (C|L) = 1 - 0.90 = 0.10 (since the probability of being open is 0.90)
Now we can calculate the total probability of the school being closed (C):
\[
P(C) = P(C|H) \cdot P(H) + P(C|L) \cdot P(L)
\]
Substituting the values we have:
\[
P(C) = (0.95 \cdot 0.65) + (0.10 \cdot 0.35)
\]
Calculating each term:
1. \( 0.95 \cdot 0.65 = 0.6175 \)
2. \( 0.10 \cdot 0.35 = 0.035 \)
Now sum these results:
\[
P(C) = 0.6175 + 0.035 = 0.6525
\]
To express this probability as a percent, we multiply by 100:
\[
P(C) = 0.6525 \times 100 = 65.25\%
\]
Thus, the probability that the school is closed tomorrow is **65.25%**.