To find the area of the polygon shaped like a capital "I," we can first visualize or outline its configuration based on the given dimensions.
From your data, we can assume the following measurements represent the width and heights of different segments of the "I":
- The total width of the "I" is 9 units.
- The height of the top bar is 2 units.
- The width of the top and bottom bars is likely 2 units each (assuming symmetry).
- The height of the vertical part is 11 units.
- The height of the bottom bar is also 2 units.
The shape can be broken down as follows:
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The area of the horizontal bars (top and bottom):
- Each top and bottom bar has an area of width * height = 9 (width) * 2 (height) = 18.
- Since there are two such bars, the total area of both bars is \(2 * 18 = 36\).
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The area of the vertical bar:
- The vertical bar has a width of 2 units and a height of 11 units (assuming it is 2 units wide throughout).
- The area of the vertical bar = width * height = 2 * 11 = 22.
Putting it all together:
- Total area = Area of top bar + Area of bottom bar + Area of vertical bar
- Total area = 18 + 18 + 22 = 58 square units.
Thus, the area of the polygon shaped like a capital "I" is 58 square units.