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Original Question
ow much larger is the calculation of the volume of a sphere's whose radius is 75 75 inches if π is used instead of 3.14? Round...Asked by nah id win
How much larger is the calculation of the volume of a sphere's whose radius is
39 inches if π is used instead of 3.14?
Round your answer to the nearest tenth.
The difference of using π rather than 3.14 is about
cubic inches.
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To find how much larger the volume calculation of a sphere is when using \( \pi \) compared to using \( 3.14 \), we'll calculate the volume of the sphere using both values.
The formula for the volume \( V \) of a sphere is:
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere.
### Step 1: Calculate the volume using \( \pi \)
Given:
- \( r = 39 \) inches
- Using \( \pi \):
\[
V_{\pi} = \frac{4}{3} \pi (39)^3
\]
Calculating \( 39^3 \):
\[
39^3 = 39 \times 39 \times 39 = 59319
\]
Now substituting back into the volume formula:
\[
V_{\pi} = \frac{4}{3} \pi (59319) \approx \frac{4}{3} \times 3.14159 \times 59319 \approx 248998.293 \text{ cubic inches}
\]
### Step 2: Calculate the volume using \( 3.14 \)
Now, we use \( 3.14 \):
\[
V_{3.14} = \frac{4}{3} (3.14) (39)^3
\]
Using \( 39^3 \) which we already calculated as \( 59319 \):
\[
V_{3.14} = \frac{4}{3} (3.14) (59319) \approx \frac{4}{3} \times 3.14 \times 59319
\]
Calculating this step-by-step:
\[
= \frac{4}{3} \times 186,659.46 \approx 248879.28 \text{ cubic inches}
\]
### Step 3: Find the difference
Now we find the difference between the two volumes:
\[
\text{Difference} = V_{\pi} - V_{3.14} \approx 248998.293 - 248879.28 \approx 119.013 \text{ cubic inches}
\]
### Step 4: Round to the nearest tenth
Rounding \( 119.013 \) to the nearest tenth gives:
\[
\text{Difference} \approx 119.0 \text{ cubic inches}
\]
### Final Result
The difference of using \( \pi \) rather than \( 3.14 \) is about **119.0 cubic inches**.
The formula for the volume \( V \) of a sphere is:
\[
V = \frac{4}{3} \pi r^3
\]
where \( r \) is the radius of the sphere.
### Step 1: Calculate the volume using \( \pi \)
Given:
- \( r = 39 \) inches
- Using \( \pi \):
\[
V_{\pi} = \frac{4}{3} \pi (39)^3
\]
Calculating \( 39^3 \):
\[
39^3 = 39 \times 39 \times 39 = 59319
\]
Now substituting back into the volume formula:
\[
V_{\pi} = \frac{4}{3} \pi (59319) \approx \frac{4}{3} \times 3.14159 \times 59319 \approx 248998.293 \text{ cubic inches}
\]
### Step 2: Calculate the volume using \( 3.14 \)
Now, we use \( 3.14 \):
\[
V_{3.14} = \frac{4}{3} (3.14) (39)^3
\]
Using \( 39^3 \) which we already calculated as \( 59319 \):
\[
V_{3.14} = \frac{4}{3} (3.14) (59319) \approx \frac{4}{3} \times 3.14 \times 59319
\]
Calculating this step-by-step:
\[
= \frac{4}{3} \times 186,659.46 \approx 248879.28 \text{ cubic inches}
\]
### Step 3: Find the difference
Now we find the difference between the two volumes:
\[
\text{Difference} = V_{\pi} - V_{3.14} \approx 248998.293 - 248879.28 \approx 119.013 \text{ cubic inches}
\]
### Step 4: Round to the nearest tenth
Rounding \( 119.013 \) to the nearest tenth gives:
\[
\text{Difference} \approx 119.0 \text{ cubic inches}
\]
### Final Result
The difference of using \( \pi \) rather than \( 3.14 \) is about **119.0 cubic inches**.
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