Question
Sara correctly find the volume of the square pyramid below to be 2268 ft³. What was the pyramid's height?
the botten os 6
and the other one is 18
the botten os 6
and the other one is 18
Answers
Answered by
GPT-4o mini
To find the height of a square pyramid, we can use the formula for the volume of a pyramid:
\[
V = \frac{1}{3} \times B \times h
\]
where \(V\) is the volume, \(B\) is the area of the base, and \(h\) is the height.
Given:
- Volume \(V = 2268 \, \text{ft}^3\)
- The side length of the base (since it's a square) is \(6 \, \text{ft}\).
First, we need to calculate the area of the base \(B\):
\[
B = \text{side}^2 = 6 \, \text{ft} \times 6 \, \text{ft} = 36 \, \text{ft}^2
\]
Now we can substitute \(V\) and \(B\) into the volume formula and solve for \(h\):
\[
2268 = \frac{1}{3} \times 36 \times h
\]
To isolate \(h\), multiply both sides by 3:
\[
2268 \times 3 = 36 \times h
\]
\[
6804 = 36h
\]
Now, divide both sides by 36:
\[
h = \frac{6804}{36}
\]
Calculating that gives:
\[
h = 189 \, \text{ft}
\]
Therefore, the height of the pyramid is \(189\) feet.
\[
V = \frac{1}{3} \times B \times h
\]
where \(V\) is the volume, \(B\) is the area of the base, and \(h\) is the height.
Given:
- Volume \(V = 2268 \, \text{ft}^3\)
- The side length of the base (since it's a square) is \(6 \, \text{ft}\).
First, we need to calculate the area of the base \(B\):
\[
B = \text{side}^2 = 6 \, \text{ft} \times 6 \, \text{ft} = 36 \, \text{ft}^2
\]
Now we can substitute \(V\) and \(B\) into the volume formula and solve for \(h\):
\[
2268 = \frac{1}{3} \times 36 \times h
\]
To isolate \(h\), multiply both sides by 3:
\[
2268 \times 3 = 36 \times h
\]
\[
6804 = 36h
\]
Now, divide both sides by 36:
\[
h = \frac{6804}{36}
\]
Calculating that gives:
\[
h = 189 \, \text{ft}
\]
Therefore, the height of the pyramid is \(189\) feet.