Question

A circular swimming pool has a radius of 15 ft. There is a path all the way around that pool that is three feet wide.

A circle has a radius of 15 feet. A larger circle goes around the smaller circle that is 3 feet wide.

What is the circumference of the outer edge of the path around the pool? Use 3.14 for Pi.
56.52 ft
94.20 ft
113.04 ft
114.04 ft

Answer 1

To find the circumference of the outer edge of the path around the pool, we first need to determine the radius of the larger circle, which includes the pool and the path.

1. **Radius of the pool**: 15 ft
2. **Width of the path**: 3 ft

The total radius of the larger circle (pool + path) is:
\[
\text{Total radius} = \text{Radius of the pool} + \text{Width of the path} = 15 \text{ ft} + 3 \text{ ft} = 18 \text{ ft}
\]

Next, we use the formula for the circumference of a circle, which is:
\[
C = 2 \pi r
\]
where \( r \) is the radius.

Now, substituting \( r = 18 \) ft and using \( \pi \approx 3.14 \):
\[
C = 2 \times 3.14 \times 18
\]

Calculating this step-by-step:
\[
C = 2 \times 3.14 = 6.28
\]
\[
C = 6.28 \times 18 = 113.04 \text{ ft}
\]

Thus, the circumference of the outer edge of the path around the pool is \( \boxed{113.04} \) ft.