Use the reaction to answer the question.3MnO42–(aq) + 4H+(aq) ⇄ 2MnO4–(aq) + 2H2O(l) + MnO2(s)In this reaction, MnO42– ions are green and MnO4– ions are purple.Which substance, when added to the solution, would make the solution more purple?(1 point)ResponsesMnO42– ionsMnO 4 2–  ionsMnO4– ionsMnO 4 – ionsH2OH 2 OMnO2MnO 2

1 answer

To make the solution more purple, you would want to increase the concentration of MnO4– ions. According to the given equilibrium reaction:

\[ 3 \text{MnO}_4^{2-} (aq) + 4 \text{H}^+ (aq) \rightleftharpoons 2 \text{MnO}_4^{-} (aq) + 2 \text{H}_2\text{O} (l) + \text{MnO}_2 (s) \]

Adding MnO4– ions directly to the solution would increase their concentration and thus make the solution more purple.

So the correct response is: MnO4– ions.