Question

Barb plans to flip a two-sided coin three times. What is
the probability that the coin will land heads up on the
first flip, tails up on the second flip, and heads up on the
third flip?

F.
0.125
G.
0.250
H.
0.375
J.
0.500
K.
0.625

Answer 1

To find the probability that Barb's two-sided coin will land heads up on the first flip, tails up on the second flip, and heads up on the third flip, we can consider the probability of each individual flip.

- The probability of flipping heads (H) on any single flip is \( \frac{1}{2} \).
- The probability of flipping tails (T) on any single flip is also \( \frac{1}{2} \).

Now, we are interested in the specific sequence of flips: H (first flip), T (second flip), H (third flip).

The probability of this sequence occurring is calculated by multiplying the probabilities of each individual result:

\[
P(H \text{ on 1st flip}) \times P(T \text{ on 2nd flip}) \times P(H \text{ on 3rd flip})
= \frac{1}{2} \times \frac{1}{2} \times \frac{1}{2}
= \frac{1}{8}
\]

Now, \( \frac{1}{8} \) is equal to 0.125.

Thus, the probability that the coin will land heads up on the first flip, tails up on the second flip, and heads up on the third flip is \( \boxed{0.125} \).