Use the following formulas to help you find the equation of a circle give two points that are on the diameter of the circle.

distance: d=(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√
midpoint: (x,y)=(x1+x22,y1+y22)
circle: (x−h)2+(y−k)2=r2(5 points)
Write the equation for a circle with a diameter AB¯¯¯¯¯¯¯¯ given coordinates A(−4,2) and B(−4,16).

Measure of the diameter of the circle:

Measure of the radius of the circle:

Center of the circle (h,k): (
,
)

Write the entire equation of the circle:

1 answer

To find the equation of a circle based on the diameter defined by points A and B, we start with the following steps:

Step 1: Find the midpoint (center of the circle)

The midpoint formula is given by:

\[ (x,y) = \left(\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2}\right) \]

Let \(A(-4, 2)\) and \(B(-4, 16)\):

\[ h = \frac{-4 + -4}{2} = \frac{-8}{2} = -4 \] \[ k = \frac{2 + 16}{2} = \frac{18}{2} = 9 \]

So, the center of the circle is \((-4, 9)\).

Step 2: Find the distance (diameter of the circle)

Using the distance formula:

\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]

Here, let \(x_1 = -4\), \(y_1 = 2\), \(x_2 = -4\), \(y_2 = 16\):

\[ d = \sqrt{((-4) - (-4))^2 + (16 - 2)^2} \]

This simplifies to:

\[ d = \sqrt{(0)^2 + (14)^2} = \sqrt{196} = 14 \]

So, the measure of the diameter of the circle is \(14\).

Step 3: Find the radius of the circle

The radius is half of the diameter:

\[ r = \frac{d}{2} = \frac{14}{2} = 7 \]

Step 4: Write the equation of the circle

The general equation of a circle is given by:

\[ (x - h)^2 + (y - k)^2 = r^2 \]

Substituting \(h = -4\), \(k = 9\), and \(r = 7\) into the equation:

\[ (x - (-4))^2 + (y - 9)^2 = 7^2 \] \[ (x + 4)^2 + (y - 9)^2 = 49 \]

Final Answers

  • Measure of the diameter of the circle: \(14\)
  • Measure of the radius of the circle: \(7\)
  • Center of the circle (h, k): \((-4, 9)\)
  • Equation of the circle: \((x + 4)^2 + (y - 9)^2 = 49\)