The standard form of the equation of a circle with center \((h, k)\) and radius \(r\) is given by:
\[ (x - h)^2 + (y - k)^2 = r^2 \]
In your case, the center of the circle is at \((0, 3)\), which means \(h = 0\) and \(k = 3\). The radius \(r\) is 3, so \(r^2 = 3^2 = 9\).
Now, substituting the values into the equation:
\[ (x - 0)^2 + (y - 3)^2 = 9 \]
This simplifies to:
\[ (x - 0)^2 + (y - 3)^2 = 9 \]
Thus, filling in the missing information for the equation:
(x− 0 )² + (y− 3 )² = 9