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Original Question
Hondo wants to buy a rain barrel. Solve for the volume of the barrel if the height is 37 inches and the diameter is 22 inches.(...Asked by Mr scarletella
Hondo wants to buy a rain barrel. Solve for the volume of the barrel if the height is 37 inches and the diameter is 22 inches.(1 point)
Responses
1,277.98 inches3
1,277.98 inches cubed
2,555.96 inches3
2,555.96 inches cubed
56,231.12 inches3
56,231.12 inches cubed
14,057.78 inches3
14,057.78 inches cubed
Responses
1,277.98 inches3
1,277.98 inches cubed
2,555.96 inches3
2,555.96 inches cubed
56,231.12 inches3
56,231.12 inches cubed
14,057.78 inches3
14,057.78 inches cubed
Answers
Answered by
GPT-4o mini
To find the volume of the rain barrel, which is in the shape of a cylinder, we can use the formula for the volume of a cylinder:
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14159.
Given:
- Height (\( h \)) = 37 inches,
- Diameter = 22 inches, so the radius \( r \) is half of the diameter:
\[
r = \frac{22}{2} = 11 \text{ inches}
\]
Now, substitute the values into the volume formula:
\[
V = \pi (11)^2 (37)
\]
Calculating \( r^2 \):
\[
11^2 = 121
\]
Now plug that into the formula:
\[
V = \pi \times 121 \times 37
\]
Calculating \( 121 \times 37 \):
\[
121 \times 37 = 4477
\]
Now, substituting back into the volume formula:
\[
V = \pi \times 4477
\]
Now, use \( \pi \approx 3.14159 \):
\[
V \approx 3.14159 \times 4477 \approx 14057.78
\]
So the volume of the rain barrel is approximately:
\[
V \approx 14,057.78 \text{ cubic inches}
\]
Thus, the correct answer is:
**14,057.78 inches cubed**.
\[
V = \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height,
- \( \pi \) is approximately 3.14159.
Given:
- Height (\( h \)) = 37 inches,
- Diameter = 22 inches, so the radius \( r \) is half of the diameter:
\[
r = \frac{22}{2} = 11 \text{ inches}
\]
Now, substitute the values into the volume formula:
\[
V = \pi (11)^2 (37)
\]
Calculating \( r^2 \):
\[
11^2 = 121
\]
Now plug that into the formula:
\[
V = \pi \times 121 \times 37
\]
Calculating \( 121 \times 37 \):
\[
121 \times 37 = 4477
\]
Now, substituting back into the volume formula:
\[
V = \pi \times 4477
\]
Now, use \( \pi \approx 3.14159 \):
\[
V \approx 3.14159 \times 4477 \approx 14057.78
\]
So the volume of the rain barrel is approximately:
\[
V \approx 14,057.78 \text{ cubic inches}
\]
Thus, the correct answer is:
**14,057.78 inches cubed**.
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