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If the central angle of a circle measures 42 degrees and the radius is 14 inches long, then how long is the arc intercepted to the nearest inch?(1 point)
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Answered by
GPT-4o mini
To find the length of the arc intercepted by a central angle, you can use the formula:
\[
\text{Arc Length} = \frac{\theta}{360} \times 2\pi r
\]
where:
- \(\theta\) is the central angle in degrees,
- \(r\) is the radius of the circle.
In this case,
- \(\theta = 42\) degrees,
- \(r = 14\) inches.
Now, plug the values into the formula:
\[
\text{Arc Length} = \frac{42}{360} \times 2\pi \times 14
\]
First, calculate \(\frac{42}{360}\):
\[
\frac{42}{360} = \frac{7}{60} \approx 0.1167
\]
Now, calculate \(2\pi \times 14\):
\[
2\pi \times 14 \approx 28\pi \approx 87.96
\]
Now, multiply these together:
\[
\text{Arc Length} \approx 0.1167 \times 87.96 \approx 10.28
\]
Rounding to the nearest inch, the arc length is approximately:
\[
\text{Arc Length} \approx 10 \text{ inches}
\]
So, the length of the arc intercepted is **10 inches**.
\[
\text{Arc Length} = \frac{\theta}{360} \times 2\pi r
\]
where:
- \(\theta\) is the central angle in degrees,
- \(r\) is the radius of the circle.
In this case,
- \(\theta = 42\) degrees,
- \(r = 14\) inches.
Now, plug the values into the formula:
\[
\text{Arc Length} = \frac{42}{360} \times 2\pi \times 14
\]
First, calculate \(\frac{42}{360}\):
\[
\frac{42}{360} = \frac{7}{60} \approx 0.1167
\]
Now, calculate \(2\pi \times 14\):
\[
2\pi \times 14 \approx 28\pi \approx 87.96
\]
Now, multiply these together:
\[
\text{Arc Length} \approx 0.1167 \times 87.96 \approx 10.28
\]
Rounding to the nearest inch, the arc length is approximately:
\[
\text{Arc Length} \approx 10 \text{ inches}
\]
So, the length of the arc intercepted is **10 inches**.
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