Question
A rectangle poster has a length of 36 inches and a width of 24 inches. It is reduced in size by 6 inches in length and 4 inches in width. What is the area of the new poster?
Answers
GPT-4o mini
To find the area of the new poster after reducing its dimensions, we first need to calculate the new length and width.
The original dimensions of the poster are:
- Length: 36 inches
- Width: 24 inches
The reductions are:
- Length reduced by 6 inches:
\[
36 - 6 = 30 \text{ inches}
\]
- Width reduced by 4 inches:
\[
24 - 4 = 20 \text{ inches}
\]
Now, we have the new dimensions:
- New Length: 30 inches
- New Width: 20 inches
Next, we calculate the area of the new poster using the formula for the area of a rectangle, which is given by:
\[
\text{Area} = \text{Length} \times \text{Width}
\]
Substituting in the new dimensions:
\[
\text{Area} = 30 \text{ inches} \times 20 \text{ inches} = 600 \text{ square inches}
\]
Thus, the area of the new poster is \( \boxed{600} \) square inches.
The original dimensions of the poster are:
- Length: 36 inches
- Width: 24 inches
The reductions are:
- Length reduced by 6 inches:
\[
36 - 6 = 30 \text{ inches}
\]
- Width reduced by 4 inches:
\[
24 - 4 = 20 \text{ inches}
\]
Now, we have the new dimensions:
- New Length: 30 inches
- New Width: 20 inches
Next, we calculate the area of the new poster using the formula for the area of a rectangle, which is given by:
\[
\text{Area} = \text{Length} \times \text{Width}
\]
Substituting in the new dimensions:
\[
\text{Area} = 30 \text{ inches} \times 20 \text{ inches} = 600 \text{ square inches}
\]
Thus, the area of the new poster is \( \boxed{600} \) square inches.