A rectangle is graphed on a coordinate plane. The table shows the original vertices and the new vertices after a scale factor with center of dilation at (0.0) is applied.

Rectangle Dilation

Vertices of Original Rectangle

(12,9)
(12,-9)
(-12,-9)
(-12,9)
Vertices of Dilated Rectangle
(8,6)
(8,-6)
(-8,-6)
(-8,6)

What rule is applied to the original rectangle to create the new rectangle?

(x,y)→ (3/2 x, 3/2 y)
(x,y)→ (2/3 x, 2/3 y)
(x,y)→ (x - 4, y - 3)
(x,y)→ (x + 4, y - 3)

1 answer

To find the rule applied to the original rectangle to create the new rectangle, we can examine the original vertices and the corresponding dilated vertices to determine the relationship.

Original vertices:

  • (12, 9)
  • (12, -9)
  • (-12, -9)
  • (-12, 9)

Dilated vertices:

  • (8, 6)
  • (8, -6)
  • (-8, -6)
  • (-8, 6)

Now let's analyze the transformation for one of the points, for example, (12, 9) to (8, 6):

For the x-coordinate:

  • From 12 to 8: \( 8 = k \cdot 12 \)
    • \( k = \frac{8}{12} = \frac{2}{3} \)

For the y-coordinate:

  • From 9 to 6: \( 6 = k \cdot 9 \)
    • \( k = \frac{6}{9} = \frac{2}{3} \)

We see that both x and y coordinates are multiplied by \(\frac{2}{3}\).

Thus, the transformation rule can be described as: \[ (x, y) \to \left(\frac{2}{3}x, \frac{2}{3}y\right) \]

Out of the options provided, the correct rule is: \[ (x,y) \to \left(\frac{2}{3}x, \frac{2}{3}y\right) \]

So the correct answer is: \((x,y)→ (2/3 x, 2/3 y)\)