Question

what is the mass In grams of 4.60 moles of iron (III) oxide

Answer 1

To calculate the mass of iron (III) oxide (Fe₂O₃) in grams for 4.60 moles, you first need to find the molar mass of Fe₂O₃.

1. **Calculate the molar mass of Fe₂O₃:**
- Iron (Fe) has a molar mass of approximately 55.85 g/mol.
- Oxygen (O) has a molar mass of approximately 16.00 g/mol.

Fe₂O₃ contains:
- 2 Iron atoms: \( 2 \times 55.85 \, \text{g/mol} = 111.70 \, \text{g/mol} \)
- 3 Oxygen atoms: \( 3 \times 16.00 \, \text{g/mol} = 48.00 \, \text{g/mol} \)

Total molar mass of Fe₂O₃:
\[
111.70 \, \text{g/mol} + 48.00 \, \text{g/mol} = 159.70 \, \text{g/mol}
\]

2. **Calculate the mass of 4.60 moles of Fe₂O₃:**
\[
\text{Mass} = \text{Number of moles} \times \text{Molar mass}
\]
\[
\text{Mass} = 4.60 \, \text{moles} \times 159.70 \, \text{g/mol} = 733.58 \, \text{g}
\]

Therefore, the mass of 4.60 moles of iron (III) oxide (Fe₂O₃) is approximately **733.58 grams**.