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solve the system of equations

3x-6y=30
y=-6

1 answer

To solve the system of equations given:

  1. \( 3x - 6y = 30 \)
  2. \( y = -6 \)

We can substitute the value of \( y \) from the second equation into the first equation.

Substituting \( y = -6 \) into the first equation:

\[ 3x - 6(-6) = 30 \] \[ 3x + 36 = 30 \] Now, subtract 36 from both sides:

\[ 3x = 30 - 36 \] \[ 3x = -6 \]

Now, divide both sides by 3:

\[ x = -2 \]

So, the solution to the system of equations is:

\[ x = -2, \quad y = -6 \]

The solution in ordered pair form is \( (-2, -6) \).