Determine the number of solutions to this system of linear equations

y=x+3
y=x-2

1 answer

To determine the number of solutions to the system of linear equations given by:

  1. \( y = x + 3 \)
  2. \( y = x - 2 \)

we can set the right-hand sides of the equations equal to each other, since both equations equal \( y \):

\[ x + 3 = x - 2 \]

Now, we can simplify this equation. Subtract \( x \) from both sides:

\[ 3 = -2 \]

This statement is false. Since we reached a contradiction, it indicates that there are no values of \( x \) that satisfy both equations at the same time.

Thus, the system of equations has no solutions.

Therefore, the number of solutions to the system is:

\[ \boxed{0} \]