Question
A cone with radius
6
6 feet and height
15
15 feet is shown.
With a radus of 6 and hight of 15
Enter the volume, in cubic feet of the cone. Round your answer to the nearest hundredth
6
6 feet and height
15
15 feet is shown.
With a radus of 6 and hight of 15
Enter the volume, in cubic feet of the cone. Round your answer to the nearest hundredth
Answers
Answered by
GPT-4o mini
To calculate the volume of a cone, you can use the formula:
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height, and
- \( \pi \) is approximately \( 3.14159 \).
Given:
- \( r = 6 \) feet
- \( h = 15 \) feet
Now, substitute the values into the formula:
\[
V = \frac{1}{3} \pi (6)^2 (15)
\]
First, calculate \( (6)^2 \):
\[
(6)^2 = 36
\]
Now substitute back into the formula:
\[
V = \frac{1}{3} \pi (36)(15)
\]
Now calculate \( 36 \times 15 \):
\[
36 \times 15 = 540
\]
Now substitute that value back:
\[
V = \frac{1}{3} \pi (540)
\]
Now divide \( 540 \) by \( 3 \):
\[
\frac{540}{3} = 180
\]
So the volume is:
\[
V = 180 \pi
\]
Now, substitute \( \pi \) with \( 3.14159 \):
\[
V \approx 180 \times 3.14159 \approx 565.486
\]
Finally, round to the nearest hundredth:
\[
V \approx 565.49
\]
Thus, the volume of the cone is approximately **565.49 cubic feet**.
\[
V = \frac{1}{3} \pi r^2 h
\]
Where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height, and
- \( \pi \) is approximately \( 3.14159 \).
Given:
- \( r = 6 \) feet
- \( h = 15 \) feet
Now, substitute the values into the formula:
\[
V = \frac{1}{3} \pi (6)^2 (15)
\]
First, calculate \( (6)^2 \):
\[
(6)^2 = 36
\]
Now substitute back into the formula:
\[
V = \frac{1}{3} \pi (36)(15)
\]
Now calculate \( 36 \times 15 \):
\[
36 \times 15 = 540
\]
Now substitute that value back:
\[
V = \frac{1}{3} \pi (540)
\]
Now divide \( 540 \) by \( 3 \):
\[
\frac{540}{3} = 180
\]
So the volume is:
\[
V = 180 \pi
\]
Now, substitute \( \pi \) with \( 3.14159 \):
\[
V \approx 180 \times 3.14159 \approx 565.486
\]
Finally, round to the nearest hundredth:
\[
V \approx 565.49
\]
Thus, the volume of the cone is approximately **565.49 cubic feet**.
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