To solve the inequality \( 60g > 3 \times 5 \), we first calculate \( 3 \times 5 \):
\[ 3 \times 5 = 15 \]
Now the inequality becomes:
\[ 60g > 15 \]
Next, we divide both sides by 60:
\[ g > \frac{15}{60} \]
Simplifying \( \frac{15}{60} \):
\[ \frac{15}{60} = \frac{1}{4} \]
So now, our simplified inequality is:
\[ g > \frac{1}{4} \]
Now we need to determine which of the given sets of numbers only includes numbers greater than \(\frac{1}{4}\):
- \( 2, 3, 4 \) (all greater than \( \frac{1}{4} \))
- \( 1, 2, 3 \) (1 is not greater than \( \frac{1}{4} \))
- \( 3, 4, 5 \) (all greater than \( \frac{1}{4} \))
- \( 4, 5, 6 \) (all greater than \( \frac{1}{4} \))
From this, we can say that the sets \( 2, 3, 4 \), \( 3, 4, 5 \), and \( 4, 5, 6 \) all contain numbers greater than \( \frac{1}{4} \). However, the set \( 1, 2, 3 \) does not satisfy this inequality because it includes the number 1.
So, the correct responses are:
- \( 2, 3, 4 \)
- \( 3, 4, 5 \)
- \( 4, 5, 6 \)
If you must choose only one option, you could select any of these three (except the second option). However, since the question format suggests a singular answer is expected, please clarify if your question indicates a different requirement (like the best solution).