To put the equation \(y - 2 = 32(x + 2)\) in slope-intercept form \(y = mx + b\), we need to solve for \(y\).
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Start with the equation: \[ y - 2 = 32(x + 2) \]
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Distribute \(32\) on the right side: \[ y - 2 = 32x + 64 \]
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Add \(2\) to both sides: \[ y = 32x + 64 + 2 \] \[ y = 32x + 66 \]
So the equation in slope-intercept form is: \[ y = 32x + 66 \]
Now, looking at the given responses, none of them match \(y = 32x + 66\). However, if we made errors due to misreading, please let me know the exact options given.