To find the y-intercepts of the functions, we can calculate them as follows:
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Function 1: \( f(x) = 4x + 2 \)
- To find the y-intercept, we set \( x = 0 \): \[ f(0) = 4(0) + 2 = 2 \] Thus, the y-intercept of Function 1 is \( (0, 2) \).
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Function 2: The y-intercept must be derived from the image, as it is a diagonal line connecting two data points. Assuming for our analysis, the y-intercept is the point where the line crosses the y-axis, which has been provided as \( (0, -2) \).
Now that we have the y-intercepts:
- Function 1: \( (0, 2) \)
- Function 2: \( (0, -2) \)
Now we compare the y-intercepts:
- The y-value for Function 1 is 2.
- The y-value for Function 2 is -2.
Since -2 is less than 2, we can conclude:
Function 2 has the smaller value.
So the correct response is: Function 1: (0, 2); Function 2: (0, -2). Function 2 has the smaller value.