Question
Here is a picture of a cube, and the net of this cube.
What is the surface area of this cube?
Enter your answer in the box.
mm²
A cube and a net of the cube are shown. The edge length of the cube is labeled 12 millimeters. The net consists of 4 squares connected horizontally, and 1 square is attached to the top of the fourth square and 1 square is attached to the bottom of the first square. One square in the net is labeled with a side labeled 12 millimeters.
What is the surface area of this cube?
Enter your answer in the box.
mm²
A cube and a net of the cube are shown. The edge length of the cube is labeled 12 millimeters. The net consists of 4 squares connected horizontally, and 1 square is attached to the top of the fourth square and 1 square is attached to the bottom of the first square. One square in the net is labeled with a side labeled 12 millimeters.
Answers
GPT-4o mini
To find the surface area of a cube, we can use the formula:
\[
\text{Surface Area} = 6s^2
\]
where \( s \) is the length of one side (or edge length) of the cube.
In your case, the edge length is given as 12 millimeters.
Now, plug the value into the formula:
\[
\text{Surface Area} = 6 \times (12 \, \text{mm})^2
\]
First, calculate \( (12 \, \text{mm})^2 \):
\[
(12 \, \text{mm})^2 = 144 \, \text{mm}^2
\]
Now, multiply that by 6:
\[
\text{Surface Area} = 6 \times 144 \, \text{mm}^2 = 864 \, \text{mm}^2
\]
Thus, the surface area of the cube is:
\[
\boxed{864 \text{ mm}^2}
\]
\[
\text{Surface Area} = 6s^2
\]
where \( s \) is the length of one side (or edge length) of the cube.
In your case, the edge length is given as 12 millimeters.
Now, plug the value into the formula:
\[
\text{Surface Area} = 6 \times (12 \, \text{mm})^2
\]
First, calculate \( (12 \, \text{mm})^2 \):
\[
(12 \, \text{mm})^2 = 144 \, \text{mm}^2
\]
Now, multiply that by 6:
\[
\text{Surface Area} = 6 \times 144 \, \text{mm}^2 = 864 \, \text{mm}^2
\]
Thus, the surface area of the cube is:
\[
\boxed{864 \text{ mm}^2}
\]