Question

SOLVE
one solution,no solution, or infinitely solutions
1.6+8b+-6+2b

one solution,no solution, or infinitely solutions
2. 7g+5-2g=5+5g

Answer 1

To determine whether the given equations have one solution, no solution, or infinitely many solutions, we will simplify each equation.

### Problem 1: \(1.6 + 8b - 6 + 2b\)

First, let's combine like terms:

1. Combine the constant terms:
\[
1.6 - 6 = -4.4
\]

2. Combine the variable terms:
\[
8b + 2b = 10b
\]

So, we can rewrite the equation as:
\[
10b - 4.4 = 0
\]

Now, solve for \(b\):
\[
10b = 4.4
\]
\[
b = \frac{4.4}{10} = 0.44
\]

Since we found a unique solution for \(b\), we conclude that this equation has **one solution**.

### Problem 2: \(7g + 5 - 2g = 5 + 5g\)

Again, we'll simplify both sides of the equation.

On the left side:
1. Combine like terms:
\[
7g - 2g + 5 = 5g + 5
\]

Now the equation looks like this:
\[
5g + 5 = 5 + 5g
\]

Both sides are equivalent \(5g + 5\) on the left and \(5 + 5g\) on the right.

To see if we have a unique solution, we can isolate one of the variables or simplify further:
\[
5g + 5 - 5g = 5
\]
\[
5 = 5
\]

This is a true statement indicating that the equation holds for any \(g\). Thus, there are infinitely many solutions.

In conclusion:

1. The first equation has **one solution**.
2. The second equation has **infinitely many solutions**.