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Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessa...Question
Apply the Pythagorean Theorem to find the length between the two points. Round your answer to the nearest hundredth, if necessary.
A: (2, -3)
B: (5, 5)
A: (2, -3)
B: (5, 5)
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Answered by
GPT-4o mini
To find the length between the two points \( A(2, -3) \) and \( B(5, 5) \), we can use the distance formula derived from the Pythagorean Theorem. The distance \( d \) between the two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by:
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
For the points \( A(2, -3) \) and \( B(5, 5) \):
- \( x_1 = 2 \)
- \( y_1 = -3 \)
- \( x_2 = 5 \)
- \( y_2 = 5 \)
Now, substitute these values into the distance formula:
\[
d = \sqrt{(5 - 2)^2 + (5 - (-3))^2}
\]
Calculating the differences:
- \( 5 - 2 = 3 \)
- \( 5 - (-3) = 5 + 3 = 8 \)
Now substitute these values back into the formula:
\[
d = \sqrt{(3)^2 + (8)^2}
\]
Calculating the squares:
- \( (3)^2 = 9 \)
- \( (8)^2 = 64 \)
Now add the squares:
\[
d = \sqrt{9 + 64} = \sqrt{73}
\]
Now we calculate the square root of 73:
\[
d \approx 8.544
\]
Rounding to the nearest hundredth:
\[
d \approx 8.54
\]
Thus, the length between the two points \( A(2, -3) \) and \( B(5, 5) \) is approximately \( \boxed{8.54} \).
\[
d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}
\]
For the points \( A(2, -3) \) and \( B(5, 5) \):
- \( x_1 = 2 \)
- \( y_1 = -3 \)
- \( x_2 = 5 \)
- \( y_2 = 5 \)
Now, substitute these values into the distance formula:
\[
d = \sqrt{(5 - 2)^2 + (5 - (-3))^2}
\]
Calculating the differences:
- \( 5 - 2 = 3 \)
- \( 5 - (-3) = 5 + 3 = 8 \)
Now substitute these values back into the formula:
\[
d = \sqrt{(3)^2 + (8)^2}
\]
Calculating the squares:
- \( (3)^2 = 9 \)
- \( (8)^2 = 64 \)
Now add the squares:
\[
d = \sqrt{9 + 64} = \sqrt{73}
\]
Now we calculate the square root of 73:
\[
d \approx 8.544
\]
Rounding to the nearest hundredth:
\[
d \approx 8.54
\]
Thus, the length between the two points \( A(2, -3) \) and \( B(5, 5) \) is approximately \( \boxed{8.54} \).
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