Question

Question
Use the image to answer the question.

An illustration shows an arrow pointing both right and left. It is formed by triangles on the right and left connected by a rectangle in the middle. The length of the rectangle measures 16 inches, and the width measures 3 inches. The perpendicular height of the triangle on the right is shown by a horizontal dotted line from the right vertex to the base. The perpendicular height measures 8 inches. The length of the base of the triangle measures 10 inches.

A school hallway has a bidirectional arrow showing which way traffic can move. The dimensions of the sign are shown. What is the arrow’s area?

(1 point)
Responses

48 in.2
48 in. squared

208 in.2
208 in. squared

80 in.2
80 in. squared

128 in.2

Answer 1

To find the area of the arrow, we need to calculate the area of the rectangle and the areas of the two triangles.

1. **Area of the rectangle**:
- Length = 16 inches
- Width = 3 inches
- Area = Length × Width = 16 in × 3 in = 48 in²

2. **Area of one triangle**:
- Base = 10 inches
- Height = 8 inches
- Area = (1/2) × Base × Height = (1/2) × 10 in × 8 in = 40 in²

Since there are two identical triangles (one on each side of the rectangle), we multiply the area of one triangle by 2:
- Total area of triangles = 2 × 40 in² = 80 in²

3. **Total area of the arrow**:
- Total area = Area of the rectangle + Area of the two triangles = 48 in² + 80 in² = 128 in²

Thus, the total area of the arrow is **128 in²**.

So, the correct answer is **128 in.²**.