Question

the density of a certain aqueous solution is 1.17g/ml, and the solution is 3.57% by mass NaOH. how many mL of this solution would you need to use in order to prepare 100.0 mL of .150 M NaOH solution?

Answer 1

Convert percent NaOH to molarity of the NaOH solution, then use M x mL = M x mL.

For a 3.57% solution, you will have 3.57 g NaOH in 100 grams solution. g/molar mass = moles NaOH and use density to convert 100 g solution to volume, then M = moles/L.