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Original Question
You roll a 6-sided die. What is P(odd or less than 2)? Simplify your answer and write it as a fraction or whole number.Asked by PJ
You roll a 6-sided die.
What is P(5 or greater than 4)?
Simplify your answer and write it as a fraction or whole number.
What is P(5 or greater than 4)?
Simplify your answer and write it as a fraction or whole number.
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Answered by
GPT-4o mini
To find the probability \( P(5 \text{ or greater than } 4) \) when rolling a 6-sided die, we first identify the outcomes on the die:
- The possible outcomes when rolling a 6-sided die are: \( 1, 2, 3, 4, 5, 6 \).
Next, we need to determine which outcomes satisfy the condition of being either 5 or greater than 4.
- The number 5 satisfies the condition.
- The numbers greater than 4 are 5 and 6.
Thus, the successful outcomes that meet the condition \( 5 \text{ or greater than } 4 \) are:
- 5
- 6
So there are 2 successful outcomes: \( 5 \) and \( 6 \).
Now we need to calculate the total number of possible outcomes when rolling the die. There are 6 possible outcomes in total.
The probability is calculated as:
\[
P(5 \text{ or greater than } 4) = \frac{\text{Number of successful outcomes}}{\text{Total number of outcomes}} = \frac{2}{6}
\]
Now we simplify the fraction:
\[
\frac{2}{6} = \frac{1}{3}
\]
Therefore, the simplified probability is:
\[
\boxed{\frac{1}{3}}
\]
- The possible outcomes when rolling a 6-sided die are: \( 1, 2, 3, 4, 5, 6 \).
Next, we need to determine which outcomes satisfy the condition of being either 5 or greater than 4.
- The number 5 satisfies the condition.
- The numbers greater than 4 are 5 and 6.
Thus, the successful outcomes that meet the condition \( 5 \text{ or greater than } 4 \) are:
- 5
- 6
So there are 2 successful outcomes: \( 5 \) and \( 6 \).
Now we need to calculate the total number of possible outcomes when rolling the die. There are 6 possible outcomes in total.
The probability is calculated as:
\[
P(5 \text{ or greater than } 4) = \frac{\text{Number of successful outcomes}}{\text{Total number of outcomes}} = \frac{2}{6}
\]
Now we simplify the fraction:
\[
\frac{2}{6} = \frac{1}{3}
\]
Therefore, the simplified probability is:
\[
\boxed{\frac{1}{3}}
\]
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