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You roll a 6-sided die.

What is P(odd or less than 2)?

Simplify your answer and write it as a fraction or whole number.

1 answer

To find the probability \( P(\text{odd or less than 2}) \) when rolling a 6-sided die, we need to identify the outcomes that satisfy the condition.

  1. The odd numbers on a 6-sided die are:

    • 1
    • 3
    • 5

    So, the odd numbers are {1, 3, 5}.

  2. The numbers that are less than 2 on a 6-sided die are:

    • 1

Now, let's combine the outcomes that are either odd or less than 2. The outcomes we have are:

  • From the odd numbers: {1, 3, 5}
  • From the numbers less than 2: {1}

The combined unique outcomes are: {1, 3, 5}.

Next, we count the total unique outcomes:

  • Total unique outcomes = 3 (which are 1, 3, and 5).

The total number of possible outcomes when rolling a 6-sided die is 6, which are {1, 2, 3, 4, 5, 6}.

Finally, to find the probability:

\[ P(\text{odd or less than 2}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{3}{6} \]

Now, simplify the fraction:

\[ \frac{3}{6} = \frac{1}{2} \]

Thus, the probability \( P(\text{odd or less than 2}) \) is \( \frac{1}{2} \).