Question

You roll a 6-sided die.




What is P(odd or less than 2)?

Simplify your answer and write it as a fraction or whole number.

Answer 1

To find the probability \( P(\text{odd or less than 2}) \) when rolling a 6-sided die, we need to identify the outcomes that satisfy the condition.

1. The odd numbers on a 6-sided die are:
- 1
- 3
- 5

So, the odd numbers are {1, 3, 5}.

2. The numbers that are less than 2 on a 6-sided die are:
- 1

Now, let's combine the outcomes that are either odd or less than 2. The outcomes we have are:
- From the odd numbers: {1, 3, 5}
- From the numbers less than 2: {1}

The combined unique outcomes are: {1, 3, 5}.

Next, we count the total unique outcomes:
- Total unique outcomes = 3 (which are 1, 3, and 5).

The total number of possible outcomes when rolling a 6-sided die is 6, which are {1, 2, 3, 4, 5, 6}.

Finally, to find the probability:

\[
P(\text{odd or less than 2}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{3}{6}
\]

Now, simplify the fraction:

\[
\frac{3}{6} = \frac{1}{2}
\]

Thus, the probability \( P(\text{odd or less than 2}) \) is \( \frac{1}{2} \).