Simplify the complex fraction.

StartStartFraction StartFraction 2 Over p plus 2 EndFraction minus 1 OverOver StartFraction 2 Over p plus 2 EndFraction plus 1 EndEndFraction

1 answer

To simplify the complex fraction

\[ \frac{\frac{2}{p+2} - 1}{\frac{2}{p+2} + 1}, \]

we will first handle the numerator and denominator separately.

Step 1: Simplify the numerator

The numerator is

\[ \frac{2}{p+2} - 1. \]

To combine these terms, we can express \(1\) as \(\frac{p+2}{p+2}\):

\[ \frac{2}{p+2} - 1 = \frac{2}{p+2} - \frac{p+2}{p+2} = \frac{2 - (p + 2)}{p + 2} = \frac{2 - p - 2}{p + 2} = \frac{-p}{p + 2}. \]

Step 2: Simplify the denominator

The denominator is

\[ \frac{2}{p+2} + 1. \]

Similarly, express \(1\) as \(\frac{p+2}{p+2}\):

\[ \frac{2}{p+2} + 1 = \frac{2}{p+2} + \frac{p+2}{p+2} = \frac{2 + (p + 2)}{p + 2} = \frac{2 + p + 2}{p + 2} = \frac{p + 4}{p + 2}. \]

Step 3: Combine the simplified numerator and denominator

Now we substitute our results back into the complex fraction:

\[ \frac{\frac{-p}{p + 2}}{\frac{p + 4}{p + 2}}. \]

Step 4: Simplify the fraction

When dividing by a fraction, we multiply by its reciprocal:

\[ \frac{-p}{p + 2} \cdot \frac{p + 2}{p + 4} = \frac{-p (p + 2)}{(p + 2)(p + 4)}. \]

Since \(p + 2\) cancels out (given \(p \neq -2\)):

\[ \frac{-p}{p + 4}. \]

Final Result

Thus, the simplified form of the complex fraction is

\[ \frac{-p}{p + 4}. \]