Use the image to answer the question.

A wheel is divided into 6 segments from the center toward circumference and labeled from the left as S, T, H, O, N, and E. The arrow of a needle points to O on the right and the circular end points to S on the left.

A spinner labeled with the letters of the word HONEST is to be spun once. Describe the probability of landing on an unshaded section in the sample space.

(1 point)
Responses

16
Start Fraction 1 over 6 End Fraction

12
Start Fraction 1 over 2 End Fraction

13
Start Fraction 1 over 3 End Fraction

3
3
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1 answer

To determine the probability of landing on an unshaded section when spinning a spinner labeled with the letters of the word "HONEST", we first need to identify the unshaded sections.

The spinner has a total of 6 segments, and they are labeled S, T, H, O, N, and E. If we consider that the spinner is equally divided and each segment represents one letter of "HONEST", we assume each segment has an equal chance of being landed on.

Now, let's analyze the probability of landing on an unshaded section:

  1. Total segments: 6 (corresponding to the letters H, O, N, E, S, T)
  2. Segments in the sample space: All 6 letters, so the sample space = {H, O, N, E, S, T} = 6 total outcomes.

Since there are no specifications in your question regarding which segments are shaded or unshaded, it can be interpreted that all segments (H, O, N, E, S, T) are unshaded.

So, if all segments are unshaded:

  • Number of unshaded segments = 6
  • Total segments = 6

The probability \( P \) of landing on an unshaded section is calculated as follows:

\[ P(\text{unshaded}) = \frac{\text{Number of Unshaded Sections}}{\text{Total Sections}} = \frac{6}{6} = 1 \]

However, if we consider "unshaded" to mean a specific subset of the sections that are not defined clearly in your question, we can select:

If your question assumes 3 of these sections (for example, H, N, and T) are unshaded, then:

  • Number of unshaded segments = 3
  • Total segments = 6

In this case:

\[ P(\text{unshaded}) = \frac{3}{6} = \frac{1}{2} \]

Thus, considering the probabilities presented as options, if 3 letters correspond to unshaded, the correct answer would be:

\[ \text{Start Fraction 1 over 2 End Fraction} \]

If all are unshaded, it would simply be 1 (which is not listed). Please verify any specifics regarding the shading of the segments in the original image to clarify the unshaded sections.