To find \( P(2 \text{ or prime}) \), we first need to identify the outcomes on a 6-sided die and the favorable outcomes for the event "2 or prime".
The outcomes on a 6-sided die are:
- 1
- 2
- 3
- 4
- 5
- 6
Next, we identify the prime numbers on this die. A prime number is a number greater than 1 that has no positive divisors other than 1 and itself. The prime numbers on a 6-sided die are:
- 2 (which is prime)
- 3 (which is prime)
- 5 (which is prime)
Now we list the outcomes that are either 2 or prime:
- 2 (is 2)
- 3 (is prime)
- 5 (is prime)
So, the favorable outcomes for the event "2 or prime" are: 2, 3, 5.
Counting these outcomes gives us:
- Total favorable outcomes: 3 (which are 2, 3, and 5)
The total number of outcomes when rolling a 6-sided die is 6.
Now, we can find the probability \( P(2 \text{ or prime}) \): \[ P(2 \text{ or prime}) = \frac{\text{Number of favorable outcomes}}{\text{Total outcomes}} = \frac{3}{6} = \frac{1}{2} \]
To express this as a percentage: \[ P(2 \text{ or prime}) \approx 0.5 \times 100% = 50% \]
Thus, \( P(2 \text{ or prime}) \) is \( \boxed{50} \).