Use the table to answer the question.

The table displays the outcomes of a spinner landing on the letters K, I, N, and D when spun by Xavier.
Outcome K I N D
Frequency 120 140 105 135
A spinner is divided into 4 sections labeled as K
, I
, N
, D
. Xavier reproduced the wheel and uses a computer to simulate the outcomes of 500 spins. What is the approximate probability that the spinner will stop on a consonant on the next spin?

(1 point)
Responses

0.45
0.45

0.72
0.72

0.28
0.28

0.24
0.24
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1 answer

To determine the probability that the spinner will stop on a consonant (K or D) when spun, we first identify the frequencies of the outcomes:

  • K: 120
  • I: 140
  • N: 105
  • D: 135

Next, we calculate the total frequency:

\[ \text{Total frequency} = 120 + 140 + 105 + 135 = 500 \]

Next, we identify the consonants in the outcomes. The consonants in this scenario are K and D:

\[ \text{Frequency of K} = 120 \] \[ \text{Frequency of D} = 135 \]

Now, we calculate the total frequency of consonants:

\[ \text{Total frequency of consonants} = 120 + 135 = 255 \]

Now, we can find the probability of stopping on a consonant by dividing the total frequency of consonants by the total frequency of all outcomes:

\[ \text{Probability} = \frac{\text{Total frequency of consonants}}{\text{Total frequency}} = \frac{255}{500} = 0.51 \]

However, we can see that none of the provided answer choices match this calculated probability. The error might lie in rounding or assumptions about the outcomes.

Since we only see other probabilities in terms given, let's take a look at our consonants:

If we consider rounding errors:

  • The first response (0.45) is lower than 0.51.
  • The second response (0.72) is higher than 0.51.
  • The third (0.28) and fourth (0.24) are also lower than 0.51.

It seems more appropriate based on proportion that none match, but we still check:

  1. K: 120/500 = 0.24
  2. D: 135/500 = 0.27
  3. Combined consonants: \(0.27 + 0.24 = 0.51\)

Therefore, it appears we must stick with what we have. Although the choices do not match with our calculations, looking closely:

Answer should reflect consonants but none match.

If asked to select based on nearest probabilities given by option, possibly round up might indicate 0.45 but is not conclusive.

Rechecking this would point it should be at least in attempts either way. Likelihood would tend towards those nearest options if we must select, but we must clarify statements deriving any outcomes directly accordingly.

A final choice would thus be 0.45 but confirmatory is strongly in rounding edges.

If absolutely needing, we say: Choose \(0.45\) as the conservative choice based on option and spin, though knowing it derives others stemming close against expectations given outcomes.