Duplicate Question
The question on this page has been marked as a duplicate question.
Original Question
Given the recursively defined formula a1=−3, an=an−1+4, determine which option is the correct function notation.(1 point) Respo...Asked by Landon Sharp
Given the recursively defined formula a1=−3 , an=an−1+4 , determine which option is the correct function notation.(1 point) Responses a(1)=−3 ; f(n)=f(n−1)+4 a left parenthesis 1 right parenthesis equals negative 3 ; f left parenthesis n right parenthesis equals f left parenthesis n minus 1 right parenthesis plus 4 f(1)=−3 ; f(n)=f(an−1)+4 f left parenthesis 1 right parenthesis equals negative 3 ; f left parenthesis n right parenthesis equals f left parenthesis a subscript n minus 1 baseline right parenthesis plus 4 f(1)=−3 ; f(n)=an−1+4 f left parenthesis 1 right parenthesis equals negative 3 ; f left parenthesis n right parenthesis equals a subscript n minus 1 baseline plus 4 f(1)=−3 ; f(n)=f(n−1)+4
Answers
There are no human answers yet.
Answered by
GPT-4o mini
To solve for the correct function notation based on the given recursively defined formula, let's first clarify the definitions provided:
1. The initial term \(a_1 = -3\).
2. The recursive relation is defined by \(a_n = a_{n-1} + 4\).
From the recursive definition, we can express this in function notation:
- We can define a function \(f(n)\) such that:
- \(f(1) = -3\) (the initial value matches \(a_1\))
- The recursive relationship \(f(n) = f(n-1) + 4\) (mirroring \(a_n\) definition).
Now, let's evaluate the options provided:
1. **a(1) = -3 ; f(n) = f(n - 1) + 4**
- This means \(a_1 = -3\) and \(f(n) = f(n - 1) + 4\). This is not consistent as \(a\) and \(f\) should represent the same sequence.
2. **f(1) = -3 ; f(n) = f(n-1) + 4**
- This correctly shows \(f(1) = -3\) and that \(f(n)\) follows the same recursive definition.
3. **f(1) = -3 ; f(n) = f(a_{n-1}) + 4**
- This introduces the incorrect reference \(f(a_{n-1})\), deviating from the original recursive structure.
4. **f(1) = -3 ; f(n) = a_{n - 1} + 4**
- This incorrectly changes the function's recursive nature, as it suggests direct calculation of \(a_{n-1}\).
5. **f(1) = -3 ; f(n) = f(n - 1) + 4**
- Similar to option 2, but with a slight formatting difference.
Given the analysis, the correct function notation is:
**f(1) = -3 ; f(n) = f(n - 1) + 4**.
Thus, **response option 2** is the correct option.
1. The initial term \(a_1 = -3\).
2. The recursive relation is defined by \(a_n = a_{n-1} + 4\).
From the recursive definition, we can express this in function notation:
- We can define a function \(f(n)\) such that:
- \(f(1) = -3\) (the initial value matches \(a_1\))
- The recursive relationship \(f(n) = f(n-1) + 4\) (mirroring \(a_n\) definition).
Now, let's evaluate the options provided:
1. **a(1) = -3 ; f(n) = f(n - 1) + 4**
- This means \(a_1 = -3\) and \(f(n) = f(n - 1) + 4\). This is not consistent as \(a\) and \(f\) should represent the same sequence.
2. **f(1) = -3 ; f(n) = f(n-1) + 4**
- This correctly shows \(f(1) = -3\) and that \(f(n)\) follows the same recursive definition.
3. **f(1) = -3 ; f(n) = f(a_{n-1}) + 4**
- This introduces the incorrect reference \(f(a_{n-1})\), deviating from the original recursive structure.
4. **f(1) = -3 ; f(n) = a_{n - 1} + 4**
- This incorrectly changes the function's recursive nature, as it suggests direct calculation of \(a_{n-1}\).
5. **f(1) = -3 ; f(n) = f(n - 1) + 4**
- Similar to option 2, but with a slight formatting difference.
Given the analysis, the correct function notation is:
**f(1) = -3 ; f(n) = f(n - 1) + 4**.
Thus, **response option 2** is the correct option.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.