Javon wants to find out the average weight of apples in his orchard without being too far off. He knows that the standard deviation is about 12 grams and he wants the margin of error to be no more than 4 grams. He also knows that for a 95% confidence level, the z-value is 1.96. To figure out how many apples he needs to sample, he can use the formula for the sample size, which is n = (z * σ / E)², where σ is the standard deviation (12 grams) and E is the margin of error (4 grams). So he does the math: n = (1.96 * 12 / 4)², which equals (5.88)² = 34.57. Since he can't sample a fraction of an apple, he rounds up to 35. Therefore, Javon needs to sample at least 35 apples to be confident in his results!
Javon wants to estimate the mean weight of apples in his orchard. He’ll sample n apples and make a 95% confidence interval for the mean weight, so z=1.96
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1.96
. He is willing to use a standard deviation of 12 grams as an estimate, and he wants the margin of error to be no more than 4 grams. What is the smallest approximate sample size required to obtain the desired margin of error? Show your work.
make it simple in a small paragraph and like a kid wrote it.
put it all in a paragraph
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