To find the mass of gold that will have the same volume as 12 grams of silver, we first need to determine the volume of silver. The formula for volume based on density is:
\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]
Using the density of silver (10.49 g/cm³), we can calculate its volume:
\[ \text{Volume of silver} = \frac{12 \text{ g}}{10.49 \text{ g/cm}^3} \approx 1.144 \text{ cm}^3 \]
Now, we will use this volume to find out how much mass of gold corresponds to that same volume. Using the density of gold (19.32 g/cm³), we can rearrange the formula to find mass:
\[ \text{Mass} = \text{Density} \times \text{Volume} \]
Substituting the volume we found and the density of gold:
\[ \text{Mass of gold} = 19.32 \text{ g/cm}^3 \times 1.144 \text{ cm}^3 \approx 22.09 \text{ g} \]
Rounding this gives us approximately 22.10 g.
Thus, the mass of gold that has the same volume as 12 grams of silver is 22.10 g.