To find the median ticket price for each theater, we need to look at the ordered list of ticket prices for both theaters.
Theater A (Ordered List):
- 39
- 42
- 45
- 48
- 51
- 54
- 57
- 60
- 63
- 66
The total number of prices for Theater A is 10 (an even number), so the median will be the average of the 5th and 6th values in the ordered list.
Median for Theater A:
- 5th value = 51
- 6th value = 54
\[ \text{Median}_{A} = \frac{51 + 54}{2} = \frac{105}{2} = 52.5 \]
Theater B (Assuming similar format):
- Let's say Theater B has values (as an example) ordered as follows:
- 30
- 36
- 42
- 45
- 50
- 55
- 60
- 65
- 70
- 75
Median for Theater B:
- 5th value = 50
- 6th value = 55
\[ \text{Median}_{B} = \frac{50 + 55}{2} = \frac{105}{2} = 52.5 \]
However, without specific values for Theater B, you'd need to replace with your actual B values.
Answers:
a. The median ticket price for Theater A is $52.5. (Replace with actual for B) b. To determine the range, subtract the minimum from the maximum price for each theater. c. The highest ticket price at either theater will be the maximum of both maximums.
Comparisons:
- Compare medians, ranges, and highest prices to draw conclusions about price distributions.
- Discuss whether one theater has consistently higher prices or a wider variation based on the box plot visual.
Please provide the specific values for Theater B if the example set does not suit your data, and I can assist you further!