Asked by demi
A motorcycle daredevil is attempting to jump across as many buses as possible (see the drawing). The takeoff ramp makes an angle è = 18.0° above the horizontal, and the landing ramp is identical to the takeoff ramp. The buses are parked side by side, and each bus is 2.74 m wide. The cyclist leaves the ramp with a speed of v = 30.0 m/s. What is the maximum number of buses over which the cyclist can jump?
Answers
Answered by
Anonymous
horizontal speed = u = constant = 30 cos 18 so find u
d = u T
so we need T (total time aloft) to know the horizontal distance, d in the air.
so how long in the air?
initial speed up = Vi = 30 sin 18
so find Vi
v = Vi - 9.8 t
at top v = 0 and t = T/2
so
T/2 = Vi/9.8
T = Vi /4.9
put that T back in d = u T to find how far it goes in the air
d = u T
so we need T (total time aloft) to know the horizontal distance, d in the air.
so how long in the air?
initial speed up = Vi = 30 sin 18
so find Vi
v = Vi - 9.8 t
at top v = 0 and t = T/2
so
T/2 = Vi/9.8
T = Vi /4.9
put that T back in d = u T to find how far it goes in the air
Answered by
yo
sick
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.