Question

What is the value of t rounded to the nearest tenth?

Right triangle with side lengths 4 m and 6 m.

Responses

52 m
52 m

7.2 m
7.2 m

7.3 m
7.3 m

10 m

Answer 1

To find the value of \( t \) in a right triangle with side lengths 4 m and 6 m, we can apply the Pythagorean theorem:

\[
c^2 = a^2 + b^2
\]

where \( c \) is the hypotenuse and \( a \) and \( b \) are the other two sides. In this case, we can take 4 m and 6 m as the lengths of the two sides.

Calculating:

\[
c^2 = 4^2 + 6^2
\]
\[
c^2 = 16 + 36
\]
\[
c^2 = 52
\]
\[
c = \sqrt{52}
\]
\[
c \approx 7.2111
\]

Now, rounding \( c \) to the nearest tenth:

\[
c \approx 7.2
\]

Thus, the value of \( t \) rounded to the nearest tenth is \( 7.2 \, \text{m} \).

So the correct response is:

**7.2 m**