Let's evaluate the equation y = 3x + 7 for the given values of x and fill in the blanks in the table.
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For x = 1, we have: \[ y = 3(1) + 7 = 3 + 7 = 10 \] (This value is already filled in the table.)
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For x = 2, we calculate: \[ y = 3(2) + 7 = 6 + 7 = 13 \] So, we can fill in the blanks:
- x = 2: Function is \( 3(2) + 7 \) and y = 13.
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For x = 3, we calculate: \[ y = 3(3) + 7 = 9 + 7 = 16 \] (This value is already filled in the table.)
Now, we can summarize the filled table:
| x | Function | y | |---|----------------|----| | 1 | 3(1) + 7 | 10 | | 2 | 3(2) + 7 | 13 | | 3 | 3(3) + 7 | 16 |
Now, the missing values in the blanks are filled as follows:
- For the second row: Function = 3(2) + 7 and y = 13.
- The third row is already complete with Function = 3(3) + 7, which gives y = 16.
So the final answers for the blanks are:
- In the second row: 7 (function part) and 13 (y-value).
- The third row is completed already.
If we wanted to represent the final filled-in row clearly:
- x = 2, Function = 3(2) + 7, y = 13.
Additionally, the values we used from the word bank are:
- 7 and 13.