The recursive formula you provided is:
\[ f(x) = f(x-1) \cdot 1.06 \] with the initial condition \( f(0) = 2000 \).
This indicates that the amount in the fund grows by a factor of \( 1.06 \) each year. Therefore, if we want to express this in a closed-form exponential equation, we can analyze the recursive relationship.
Starting with the base case:
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For \( x = 0 \): \[ f(0) = 2000 \]
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For \( x = 1 \): \[ f(1) = f(0) \cdot 1.06 = 2000 \cdot 1.06 \]
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For \( x = 2 \): \[ f(2) = f(1) \cdot 1.06 = (2000 \cdot 1.06) \cdot 1.06 = 2000 \cdot (1.06)^2 \]
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For \( x = t \): \[ f(t) = 2000 \cdot (1.06)^t \]
This leads us to the closed-form equation, which represents the amount in the fund after \( t \) years as:
\[ A = 2000 \cdot 1.06^t \]
Among the provided options, the correct equation is:
\[ A = 2000 \cdot 1.06^t \]