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Write the linear equation 3y=6x−18

in slope-intercept form.(1 point)
y=[
]

1 answer

To rewrite the equation \(3y = 6x - 18\) in slope-intercept form (which is \(y = mx + b\)), you need to solve for \(y\).

  1. Start with the given equation: \[ 3y = 6x - 18 \]

  2. Divide every term by 3 to isolate \(y\): \[ y = \frac{6x}{3} - \frac{18}{3} \]

  3. Simplify: \[ y = 2x - 6 \]

So, in slope-intercept form, the equation is: \[ y = 2x - 6 \]

Thus, the value of \(y\) is: \[ y = 2x - 6 \]